otp.MultiOutputSource#
- class MultiOutputSource[source]#
Bases:
object
Construct a multi-output source object from several connected otp.Source objects
This object can be saved to disk as a graph using to_otq() method, or passed to otp.run() function. If it’s passed to otp.run(), then returned results for different outputs will be available as a dictionary.
- Parameters
outputs (dict) – Dictionary which keys are names of the output sources, and values are output sources themselves. All the passed sources should be connected.
Examples
Results for individual outputs can be accessed by output names
>>> root = otp.Tick(A=1) >>> branch_1 = root.copy() >>> branch_2 = root.copy() >>> branch_3 = root.copy() >>> branch_1['B'] = 1 >>> branch_2['B'] = 2 >>> branch_3['B'] = 3 >>> src = otp.MultiOutputSource(dict(BRANCH1=branch_1, BRANCH2=branch_2, BRANCH3=branch_3)) >>> res = otp.run(src) >>> sorted(list(res.keys())) ['BRANCH1', 'BRANCH2', 'BRANCH3'] >>> res['BRANCH1'][['A', 'B']] A B 0 1 1 >>> res['BRANCH2'][['A', 'B']] A B 0 1 2 >>> res['BRANCH3'][['A', 'B']] A B 0 1 3
node_name parameter of the otp.run() method can be used to select outputs
>>> src = otp.MultiOutputSource(dict(BRANCH1=branch_1, BRANCH2=branch_2, BRANCH3=branch_3)) >>> res = otp.run(src, node_name=['BRANCH2', 'BRANCH3']) >>> sorted(list(res.keys())) ['BRANCH2', 'BRANCH3'] >>> res['BRANCH2'][['A', 'B']] A B 0 1 2 >>> res['BRANCH3'][['A', 'B']] A B 0 1 3
If only one output is selected, then it’s returned directly and not in a dictionary
>>> src = otp.MultiOutputSource(dict(BRANCH1=branch_1, BRANCH2=branch_2, BRANCH3=branch_3)) >>> res = otp.run(src, node_name='BRANCH2') >>> res[['A', 'B']] A B 0 1 2
A dictionary with sources can also be passed to otp.run directly, and MultiOutputSource object will be constructed internally
>>> res = otp.run(dict(BRANCH1=branch_1, BRANCH2=branch_2)) >>> res['BRANCH1'][['A', 'B']] A B 0 1 1 >>> res['BRANCH2'][['A', 'B']] A B 0 1 2